7x^2+17x-13=17

Solution for 7x^2+17x-13=17 equation:

7x^2+17x-13=17

We move all terms to the left:

7x^2+17x-13-(17)=0

We add all the numbers together, and all the variables

7x^2+17x-30=0

a = 7; b = 17; c = -30;
Δ = b2-4ac
Δ = 172-4·7·(-30)
Δ = 1129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{1129}}{2*7}=\frac{-17-\sqrt{1129}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{1129}}{2*7}=\frac{-17+\sqrt{1129}}{14}
$